This question was previously asked in

NDA (Held On: 22 April 2018) Maths Previous Year paper

Option 2 : 4.9

Group X 2021 Full Mock Test

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70 Questions
70 Marks
60 Mins

__Concept:__

**Median: **Let a data of n observations is given, then for finding median first arrange the observation either in increasing order or decreasing order.

- If n is odd, median \(= {\left( {\frac{{\rm{n}}}{2}} \right)^{{\rm{th}}}}\) term.
- If n is even, median \(= \frac{{{{\left( {\frac{{\rm{n}}}{2}} \right)}^{{\rm{th}}}}{\rm{term\;}} + {{\left( {\frac{{{\rm{n}} + 1}}{2}} \right)}^{{\rm{th}}}}{\rm{term}}}}{2}\)

__Calculation:__

Arranging the given observation in increasing order,

-4.8, 0, 2.6, 3.5, 3.9, 4.6, 5.2, 6.1, 7.6, 8.2, 9.3, 12.7

Number of observation, n = 12

So, we know that if n is even for median then,

Median \(= \frac{{{{\left( {\frac{{\rm{n}}}{2}} \right)}^{{\rm{th}}}}{\rm{term\;}} + {{\left( {\frac{{{\rm{n}} + 1}}{2}} \right)}^{{\rm{th}}}}{\rm{term}}}}{2}\)

\( = \frac{{4.6\; +\; 5.2}}{2}\)

= 9.8/2

= 4.9